solve for x:2x^2+6root3x-60=0
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2x^2+6root3x - 60 =0
sum = 6root3x
product = -120
numbers = 10root3x and -4root 3x
therefore,
2x^2 + 10root3x - 4root3x - 120 =0
2x (x+5root3) - 4root3 (x+5root3 )
by solving ,
x = -5root3 , -4root3/2
hope this be useful
thnx
sum = 6root3x
product = -120
numbers = 10root3x and -4root 3x
therefore,
2x^2 + 10root3x - 4root3x - 120 =0
2x (x+5root3) - 4root3 (x+5root3 )
by solving ,
x = -5root3 , -4root3/2
hope this be useful
thnx
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