Math, asked by jaffarbilal79, 3 months ago

Solve for x:
(2x + 3) (5 + x)=0​

Answers

Answered by tejassubhashjagdale
1

Step-by-step explanation:

1

Rearrange terms

(

2

+

3

)

(

5

+

)

=

0

(

2

+

3

)

(

+

5

)

=

0

2

Combine multiplied terms into a single fraction

(

2

+

3

)

(

+

5

)

=

0

(

+

5

)

2

+

3

=

0

3

Distribute

(

+

5

)

2

+

3

=

0

2

+

5

2

+

3

=

0

4

Multiply all terms by the same value to eliminate fraction denominators

2

+

5

2

+

3

=

0

(

2

+

3

)

(

2

+

5

2

+

3

)

=

0

5

Cancel multiplied terms that are in the denominator

(

2

+

3

)

(

2

+

5

2

+

3

)

=

0

2

+

5

=

0

6

Use the quadratic formula

=

±

2

4

2

x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}

x=2a−b±b2−4ac

Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.

2

+

5

=

0

x^{2}+5x=0

x2+5x=0

=

1

a={\color{#c92786}{1}}

a=1

=

5

b={\color{#e8710a}{5}}

b=5

=

0

c={\color{#129eaf}{0}}

c=0

=

5

±

5

2

4

1

0

2

1

7

Simplify

Evaluate the exponent

Multiply by zero

Add the numbers

Evaluate the square root

Multiply the numbers

=

5

±

5

2

8

Separate the equations

To solve for the unknown variable, separate into two equations: one with a plus and the other with a minus.

=

5

+

5

2

=

5

5

2

9

Solve

Rearrange and isolate the variable to find each solution

=

0

=

5

Answered by monsta34
0

(2x + 3)(5 + x) = 0 \\

Therefore :

Either

(2x + 3) = 0 \\  =  > x =  \frac{ -3}{2}

Or

(5 + x) = 0 \\  =  > x =  - 5

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