solve for x:
(2x-3/x-1) -4(x-1/2x-3)=3
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Obviously, the given equation is valid if x - 3≠0 and 2x + 3≠0. Multiplying throughout by (x - 3) (2x - 3), we get 2x(2x + 3) + 1(x - 3) + 3x + 9 = 0 or 4x2 + 10 + 6 = 0 or 2x2 + 5x + 3 = 0 or (2x + 3) (x + 1) = 0 But 2x + 3≠ 0, so we get x + 1 = 0. This gives x = - 1 as the only solution of the given equation.Read more on Sarthaks.com - https://www.sarthaks.com/253214/solve-2x-x-3-1-2x-3-3x-9-x-3-2x-3-0
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