Question

solve for x, 2x square +6root 3x - 60=0​

Answer 1

Answer:

Step-by-step explanation:

The first term is, 2x2 its coefficient is 2 .

The middle term is, +3x its coefficient is 3 .

The last term, "the constant", is -60

Step-1 : Multiply the coefficient of the first term by the constant 2 • -60 = -120

Step-2 : Find two factors of -120 whose sum equals the coefficient of the middle term, which is 3 .

-120 + 1 = -119

-60 + 2 = -58

-40 + 3 = -37

-30 + 4 = -26

-24 + 5 = -19

-20 + 6 = -14

-15 + 8 = -7

-12 + 10 = -2

-10 + 12 = 2

-8 + 15 = 7

-6 + 20 = 14

-5 + 24 = 19

-4 + 30 = 26

-3 + 40 = 37

-2 + 60 = 58

-1 + 120 = 119

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

Equation at the end of step

2

:

2x2 + 3x - 60 = 0

Answer 2

Answer: root3, -2root3

Step-by-step explanation:

For 2x^2+6root3x-60=0, there are no roots. Instead for 2x^2+6root3x-6=0, the solution is,

Divide the equation by 2,

We get x^2+3root3x-3=0,

Splitting the factors we get,

x^2+2root3x+root3x-3=0,

Take x and -root 3 common,

x(x+2root3) -root3(x+2root3) =0

(x-root3) (x+2root3) =0

x-root3=0, x+2root3=0

x=root3, x=-2root3

Hence, the roots are root3, -2root3.