Math, asked by sweetpragyaraj, 10 months ago

Solve for x: 2x/x-3 + 1/2x+3 + 3x+9/(x-3)(2x+3) = 0?

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Answered by ItsSpiderman44
17

Answer:

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Answered by Anonymous
3

Answer:

Step-by-step explanation:

Solution :-

Here, we have

⇒ 2x/(x - 3) + 1/(2x + 3) + (3x + 9)/(x - 3) (2x + 3) = 0

By Multiplying throughout by (x - 3) (2x + 3), we get

⇒ 2x(2x + 3) + (x - 3) + 3x + 9 = 0

⇒ 4x² + 6x + x - 3 + 3x + 9 = 0

⇒ 4x² + 10x + 6 = 0

Divining eq by 2, we get

⇒ 2x² + 5x + 3 = 0

By using factorization method, we get

⇒ 2x² + 5x + 3 = 0

⇒ 2x² + 2x + 3x + 3 = 0

⇒ 2x(x + 1) + 3(x + 1) = 0

⇒ (x + 1) (2x + 3) = 0

⇒ x + 1 = 0 or 2x + 3 = 0

⇒ x = - 1, - 3/2

Here, x = - 1, - 3/2.

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