Question

solve for x :(2x÷x-5)^2 +(10x÷ x-5 )-24=0

Answer 1

i think this may help you

Answer 2

x = 4 or 15  if {2x/(x - 5) }²   + 10x/(x - 5)   - 24  = 0

Step-by-step explanation:

{2x/(x - 5) }²   + 10x/(x - 5)   - 24  = 0

multiplying by (x - 5)² both sides

=> 4x² + 10x(x - 5) - 24(x - 5)² = 0

Dividing by 2 both sides

=> 2x² + 5x(x - 5) - 12(x² -10x + 25) = 0

=> 2x² + 5x² - 25x - 12x² + 120x - 300 =0

=> -5x² +95x  - 300 =0

=> x² - 19x  + 60 = 0

=> x² -4x - 15x + 60 = 0

=> x(x - 4) - 15(x - 4) =0

=> (x - 15)(x - 4) =0

=> x = 4 or 15

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