Math, asked by gharshithsai, 6 months ago

solve for x: (2x/x-5)^2+5(2x/x-5)-24=0 where x is not equal to 5

Answers

Answered by leishasri
1

Answer:

15 or 4

Step-by-step explanation:

let 2x/x-5 be a

a^2 + 5a - 24 =0

a^2 +8a -3a -24

a(a+8) - 3(a+8)

(a+8)(a-3)

now put value of a

2x/x-5 - 3 =0

2x/x-5 = 3

2x=3x-15

x=15

in second case

2x/x-5 +8 =0

2x / x-5=-8

2x = -8x +40

10 x =40

x=4

so value of can be 4 and 15 both will satisfy the equation

Answered by akleshbastia40
0

Answer:

bhai boht asan h khud karle

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