Solve for x √2x²+7x+5=0
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Answer:
x = -1 and x = -5/2.
Explanation:
To solve for x in the equation √2x²+7x+5=0, we can first square both sides of the equation to get rid of the square root:
2x² + 7x + 5 = 0
Now we can use the quadratic formula to solve for x:
x = (-b ± √(b² - 4ac)) / 2a
where a = 2, b = 7, and c = 5.
Plugging these values into the formula, we get:
x = (-7 ± √(7² - 4(2)(5))) / 2(2)
x = (-7 ± √9) / 4
Simplifying the square root:
x = (-7 ± 3) / 4
So we have two possible solutions:
x = (-7 + 3) / 4 = -1
or
x = (-7 - 3) / 4 = -5/2
Therefore, the solutions to the equation √2x²+7x+5=0 are x = -1 and x= -5/2
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