CBSE BOARD X, asked by ambika05449, 5 hours ago

Solve for x √2x²+7x+5=0​

Answers

Answered by akhilsingh0031
0

Answer:

x = -1 and x = -5/2.

Explanation:

To solve for x in the equation √2x²+7x+5=0, we can first square both sides of the equation to get rid of the square root:

2x² + 7x + 5 = 0

Now we can use the quadratic formula to solve for x:

x = (-b ± √(b² - 4ac)) / 2a

where a = 2, b = 7, and c = 5.

Plugging these values into the formula, we get:

x = (-7 ± √(7² - 4(2)(5))) / 2(2)

x = (-7 ± √9) / 4

Simplifying the square root:

x = (-7 ± 3) / 4

So we have two possible solutions:

x = (-7 + 3) / 4 = -1

or

x = (-7 - 3) / 4 = -5/2

Therefore, the solutions to the equation √2x²+7x+5=0 are x = -1 and x= -5/2

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