solve for x: 2x² - ax + a²=0
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Answer:
x=
2
a
,−a is the value of the quadratic equation \bold{2 x^{2}+a x-a^{2}=0.}2x
2
+ax−a
2
=0.
Given:
2 x^{2}+a x-a^{2}=02x
2
+ax−a
2
=0
To find:
Value of x=?
Solution:
To solve the equation 2 x^{2}+a x-a^{2}=02x
2
+ax−a
2
=0 , we have to first find the value of the “a” in the equation 2 x^{2}+a x-a^{2}=02x
2
+ax−a
2
=0
We will use the separation method that is finding the common factor we get
2 x^{2}+a x-a^{2}=02x
2
+ax−a
2
=0
2 x^{2}+2 a x-a x-a^{2}=02x
2
+2ax−ax−a
2
=0
Now subtracting axax from 2ax2ax we get
\begin{gathered}\begin{array}{l}{2 x(x+a)-a(x+a)=0} \\ {2 x-a, x+a}\end{array}\end{gathered}
2x(x+a)−a(x+a)=0
2x−a,x+a
After solving the quadratic equation for the value of “a” we get the value of: “x” as x=\frac{a}{2},-ax=
2
a
,−a
Therefore, the value of the quadratic equation after solving is \bold{x=\frac{a}{2},-a}x=
2
a
,−a
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