Solve for x: 3√3x² + x + √3 = 0
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√3x 2
−2√2x−2√3=0
√3x 2
−3√2x+2√2x−2√3=0
√3x(x−√6)+√2(x−√6)=0
either (√3x+√2)=0 or (x−√6)=0
x=√6 or −2√2/√3
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