Question

solve for x 3^4x+1 = (27)^x+1​

Answer 1

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${3}^{4x + 1} = {27}^{x + 1}$

${3}^{4x} \times {3}^{1} = { ({3}^{3}) }^{x + 1}$

${3}^{4x} \times {3}^{1} = {3}^{3x} \times {3}^{3}$

$\frac{ {3}^{4x} }{ {3}^{3x} } = \frac{ {3}^{3} }{ {3}^{1} }$

${3}^{4x - 3x} = {3}^{3 - 1}$

${3}^{x} = {3}^{2}$

$x = 2$

Answer 2

Step-by-step explanation:

27 = 3³

so

3^4x+1 = 3^3(x+1)

since bases are same powers can be equated

4x + 1 = 3(x+1)

x = 2