Math, asked by chakri24478, 1 day ago

solve for x. 3/5(x+1) -1/2(1-3x) =x​

Answers

Answered by udanchu07
1

Answer:

3/5x-1/3x=x-1

We move all terms to the left:

3/5x-1/3x-(x-1)=0

Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R

Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R

We get rid of parentheses

3/5x-1/3x-x+1=0

We calculate fractions

-x+9x/15x^2+(-5x)/15x^2+1=0

We add all the numbers together, and all the variables

-1x+9x/15x^2+(-5x)/15x^2+1=0

We multiply all the terms by the denominator

-1x*15x^2+9x+(-5x)+1*15x^2=0

We add all the numbers together, and all the variables

9x-1x*15x^2+(-5x)+1*15x^2=0

Wy multiply elements

-15x^3+15x^2+9x+(-5x)=0

We get rid of parentheses

-15x^3+15x^2+9x-5x=0

We do not support expression: x^3

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2x-2=8 x-3=5 3x+2=18 2x+10=12 6x-2=14 3x=12 4x-2=12 9x-3=6 12+x=5 x+8=13 all equations

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