Question

Solve for x: 3(7x+1/5x-3)-4(5x-3/7x+1)=11; x≠3/5,-1/7

Answer 1

here is your answer ⬆⬆⬆⬆⬆⬆

hope it helps

Answer 2

$3 \times \dfrac{7x + 1}{5x - 1} - 4 \times \dfrac{5x - 3}{7x + 1} = 11, x \neq \dfrac{3}{5}, \dfrac{-1}{7}$

Solve by using substitution

☛ $3t - 4 \times \dfrac{1}{t} = 11$

Solve the equation

☛ $t = 4$
$t = -\dfrac{1}{3}$

Return substituted values

☛ $\dfrac{7x + 1}{5x - 3} = 4$
$\dfrac{7x + 1}{5x - 3} = -\dfrac{1}{3}$

Solve the equations

☛ $x = 1\:or\:x = 0, x \neq \dfrac{3}{5}, \dfrac{-1}{7}$

Check if the solution is in the defined range

☛ $x = 1\:or\:x = 0$

The final solutions are

☛ $x_1 = 1, x_2 = 0$