Solve for x:
3^(x+1) + 3^(2x+1) = 270
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3x+1+32x+1=270.
⇒3.3x+32x.3=270
⇒3x+32x=90
Substituting 3x=a we get a+a2=90
⇒a2+a−90=0⇒a2+10a−9a−90=0
⇒(a+10)(a−9)=0⇒a=9 or a=−10
If 3x=9 then x = 2 If 3x=−10 which is not possible
∴x=2
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