Question

solve for x--???...​

Answer 1

Given:

• $\sf 3 - \sqrt{3.3} + 4 \sqrt{3} x \bigg\lgroup \frac{3 \sqrt{5}}{34 \sqrt{3} } \bigg\rgroup = 0$

Need to find:

• The value of x ?

Solution:

$: \implies \sf \: \: 3 - \sqrt{3.3} + 4 \sqrt{3} x \frac{3 \sqrt{5}}{34 \sqrt{3} } = 0 \\ \\ : \implies \sf \: 3 - \sqrt{3.3} = - 4 \sqrt{3x} \frac{3 \sqrt{5} }{34 \sqrt{3} } \\ \\ : \implies \sf 3 - \sqrt{3.3} = 2x \frac{3 \sqrt{5} }{17} \\ \\ : \implies \sf x \: = \frac{- 17(3 - \sqrt{3.3})}{2 \times 3 \sqrt{5} } \\ \\ : \implies \sf x \: = \frac{- 17(3 - \sqrt{3.3})}{6\sqrt{5} } \\ \\ : \implies \sf \frac{17( {\sqrt{3 }- 1) } }{2 \sqrt{5} }$

$:\implies{\boxed{\frak{\pink{ \frac{17( {\sqrt{3 }- 1) } }{2 \sqrt{5} }}}}}\;\bigstar$

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