Question

solve for x
3x^ 2 + 18x + 27 = 0​

Answer 1

Answer:

Hey here's your answer

Answer 2

• METHOD 1

$3x^{2} +18x+27=0\\COMPARING\: IT \:WITH \\ax^{2} +bx+c=0\\We get \\a=3\\b=18\\c=27\\\bold{Using\:x=\frac{-b\frac{+}{}\sqrt{b^{2}-4ac } }{2a} }\\substituting values of a,b,c we get \\x=\frac{-18\frac{+}{}\sqrt{18^{2}-4(3)(27) } }{2\times3} \\x=\frac{-18\frac{+}{}\sqrt{324-324} }{6} \\x=\frac{-18\frac{+}{}\sqrt{0} }{6} \\x=\frac{-18}{6} \\\blue{x=-6}$

• Method 2

$3x^{2} +18x+27=0\\Dividing\: Each \:term \:by \:3\\\\frac{3x^{2} }{3} +\frac{18x}{3} +\frac{27}{3} =\frac{0}{3} \\\\x^{2} +6x+9=0\\\\(x^{2} +3x)+(3x+9)=0\\x(x+3)+3(x+3)=0\\(x+3)(x+3)=0\\x+3=0\\x=0-3\\x=-3$

$\bold\blue{Hope it Helps }$