Question

solve for x 3x^2+5x+1=0 ​

Answer 1

$3x {}^{2} + 5x + 1$

$x = - b + - \sqrt{b {}^{2} - 4ac} \div 2a \\ x = - 5 + - \sqrt{25 - 12} \div 6$

$x = - 5 + - \sqrt{13} \div 6 \\ so \: x \: values \: are \\ x = - 5 + \sqrt{13 } \div 6 \: (or) \\ \: x = - 5 - \sqrt{13} \div 6$

Answer 2

Step-by-step explanation:

3x

2

+5x+1

\begin{lgathered}x = - b + - \sqrt{b {}^{2} - 4ac} \div 2a \\ x = - 5 + - \sqrt{25 - 12} \div 6 \\\end{lgathered}

x=−b+−

b

2

−4ac

÷2a

x=−5+−

25−12

÷6

\begin{lgathered}x = - 5 + - \sqrt{13} \div 6 \\ so \: x \: values \: are \\ x = - 5 + \sqrt{13 } \div 6 \: (or) \\ \: x = - 5 - \sqrt{13} \div 6\end{lgathered}

x=−5+−

13

÷6

soxvaluesare

x=−5+

13

÷6(or)

x=−5−

13

÷6