Question

solve for x; √3x ( √3x + 1 ) = 3x² + ( √3 + 1 ) x - 7​

Answer 1

Answer:

Hi friend!!

√3x² + 10x + 7√3 = 0

√3x² + 7x + 3x + 7√3 = 0

x(√3x + 7) + √3(√3x + 7) = 0

(√3x + 7) (x + √3) = 0

=> √3x + 7 = 0

√3x = -7

x = -7/√3

=> x + √3 = 0

x = -√3

Therefore, -7/√3 and -√3 are zeroes of the polynomial.

Hope it helps!!