solve for x :
√3x²-2√2x-2√3=0
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Answered by
0
Step-by-step explanation:
√3x
2
−2√2x−2√3=0
√3x
2
−3√2x+2√2x−2√3=0
√3x(x−√6)+√2(x−√6)=0
either (√3x+√2)=0 or (x−√6)=0
x=√6 or −2√2/√3
Answered by
1
Step-by-step explanation:
√3x2 - 2√2x - 2√3 = 0
√3x2 - 3√2x + √2x - 2√3 = 0
√3x ( x - √6 ) + √2 ( x - √6 ) = 0
( √3x + √2 ) ( x - √6 ) = 0
√3x + √2 = 0 or x - √6 = 0
x = - √2/√3 = - √6/3 or x = √6
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