Question

solve for x = √3x²-2√2x-2√3=0

Answer 1

$\sqrt{3} {x}^{2} - 2 \sqrt{2} x - 2 \sqrt{3} = 0 \\ = > \sqrt{3 } {x}^{2} - (3\sqrt{2} - \sqrt{2} )x - 2 \sqrt{3} = 0 \\ = > \sqrt{3} {x}^{2} - 3 \sqrt{2} x + \sqrt{2} x - 2 \sqrt{3} = 0 \\ = > \sqrt{3}x (x - \sqrt{6} ) + \sqrt{2} (x - \sqrt{6} ) = 0\\ = > (x - \sqrt{6} )( \sqrt{3} x + \sqrt{2} ) = 0 \\ = > x - \sqrt{6} = 0 \: \: or \: \: \sqrt{3} x + \sqrt{2} = 0 \\ = > x = \sqrt{6} \: \: or \: \: x = \frac{ - \sqrt{2} }{ \sqrt{3} }$
Hope it'll help..:)