solve for x :3x2-2√6+2=0
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Answer:
Step-by-step explanation:
3x^2 - 2√6x + 2 = 0
3x^2 - √6x -√6x + 2 = 0
√3x(√3x-√2) - √2(√3x-√2) = 0
(√3x-√2)(√3x-√2) = 0
x = √2/√3
ANOTHER METHOD:
3x^2 - 2√6x + 2 = 0
(√3x)^2 - 2(√3)(√2) + (√2)^2 = 0
Using (a+b)^2 identity
(√3x-√2)^2 = 0
Taking square root on both sides
√3x-√2 = 0
x = √2/√3
manoj12493:
thank you for help
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