Math, asked by manoj12493, 11 months ago

solve for x :3x2-2√6+2=0​

Answers

Answered by srkg5254
9

Answer:

Step-by-step explanation:

3x^2 - 2√6x + 2 = 0

3x^2 - √6x -√6x + 2 = 0

√3x(√3x-√2) - √2(√3x-√2) = 0

(√3x-√2)(√3x-√2) = 0

x = √2/√3

ANOTHER METHOD:

3x^2 - 2√6x + 2 = 0

(√3x)^2 - 2(√3)(√2) + (√2)^2 = 0

Using (a+b)^2 identity

(√3x-√2)^2 = 0

Taking square root on both sides

√3x-√2 = 0

x = √2/√3


manoj12493: thank you for help
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