solve for x :
4+3(x+2)=(x+4) +3x
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Answer:
4 + 3(x + 2) = (x + 4) + 3x \\ = 7(x + 2) = (x + 4) + 3x \\ = 7x + 14 = x + 4 + 3x \\ = 7x - x - 3 = 4 - 14 \\ = 6x - 3x = 10 \\ = 3x = 10 \\ = x = 10 \div 3 \\ = x = 3 \times \frac{1}{3} [/tex]
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Step-by-step-explanation
4 + 3(x+2) = (x+4) + 3x
Remove brackets & multiply terms
4 + 3x + 6 = x+ 4 + 3x
10 + 3x = 4x + 4
Transpose Like terms to a side
10 - 4 = 4x -3x
6 = x
x = 6
Verification:
Substuite value of x to get LHS=RHS
4 + 3(x + 2) = (x+4) + 3x
Substuite x = 6
4 + 3(6+2) = (6+4) + 3(6)
4+3(8) = 10 + 18
4 + 24 = 28
28 = 28
If we substuite x = 6 Its LHS = RHS
So, value of x is 6
Verified !
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