Question

solve for x 4√3x2+5x-2√3=0​

Answer 1

Step-by-step explanation:

Solving for x, by using quadratic equations formula,

x = (-b ± √(b²-4ac))/2a

Now, substituting a=4√3, b=5, c=-2√3, we have

x = (-5 ± √(5²-4×4√3×(-2√3)))/(2×4√3)

x = (-5 ± √(25+4×4×2×3))/8√3

x = (-5 ± √(25+96))/8√3

x = (-5 ± √121)/8√3

x = (-5 ± 11)/8√3

x = (-5-11)/8√3 or x = (-5+11)/8√3

x = -16/8√3 or x = 6/8√3

x = -2/√3 or x = 3/4√3

x = -2/√3 or x = √3/4

$x = - 2 \div \sqrt{3} \\ or \\ x = \sqrt{3} \div 4$