Math, asked by bhumi8495, 5 months ago

solve for x (4/7)^3 ÷ (7/4)^5 = (4/7)^x-2​

Answers

Answered by padigarbhavani
14

Answer:

Hey mate! Here's your answer:

Step-by-step explanation:

(4/7)³ ÷ (7/4)⁵ = (4/7)^(x - 2)

(4/7)³ ÷ (4/7)-⁵ = (4/7)^(x - 2) (4/7 raised to -5)

Now, by a^m ÷ a^n = a^ (m - n),

3 - (-5) = x - 2

3 + 5 = x - 2

x = 3 + 5 + 2

x = 10.

HOPE IT HELPS, PLS MARK IT AS THE BRAINLIEST AND PLS FOLLOW ME! :):):)

Similar questions