solve for x???????????????
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Step-by-step explanation:
It can be written as
Log x / log 4 = log (5x-6) / log 16
Log x / log 4 = log (5x-6) / log 4^2
Log x / log 4 = log (5x-6) / 2*log 4
2*Log x / log 4 = log (5x-6) / log 4
Cancel log 4 both sides in denominator
2*log x = log(5x-6)
Log (x^2) = log (5x-6)
Taking antilog both sides
x^2 = 5x-6
x^2-5x+6=0
x^2-2x-3x+6=0
x(x-2)-3(x-2)=0
(x-3)(x-2)=0
x=3, x=2
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