Math, asked by AKS828, 1 month ago

solve for x???????????????​

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Answered by akky0020
0

Step-by-step explanation:

It can be written as

Log x / log 4 = log (5x-6) / log 16

Log x / log 4 = log (5x-6) / log 4^2

Log x / log 4 = log (5x-6) / 2*log 4

2*Log x / log 4 = log (5x-6) / log 4

Cancel log 4 both sides in denominator

2*log x = log(5x-6)

Log (x^2) = log (5x-6)

Taking antilog both sides

x^2 = 5x-6

x^2-5x+6=0

x^2-2x-3x+6=0

x(x-2)-3(x-2)=0

(x-3)(x-2)=0

x=3, x=2

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