Math, asked by deeksha2678, 12 days ago

solve for x 4²x+⁵ = 64
pls tell fast ​

Answers

Answered by Sardrni
2

Answer:

X = -1

Step-by-step explanation:

Given:

4^(2x+5)=64

To solve this problem, first thing you do is isolate by the x on one side of the equation.

Solutions:

You can also used order of operations PEMDAS and BOMDAS.

BOMDAS stands for (Brackets, Of, Multiply, Divide, Add, and Subtract) the numbers from left to right.

PEMDAS stands for (Parenthesis, Exponents, Multiply, Divide, Add, and Subtract) the numbers from left to right.

First, you have to solve with exponent.

4³ = = 4*4*4 = 64

Secondly, you have to rewrite the whole problem down.

4²x+5 43 =

\displaystyle f(x)=a^g^(^x^)=f(x)=g(x)

2x + 5 = 3

Solve.

Subtract by 5 from both sides.

2x+553-5

Solve.

2x = -2

Then, divide by 2 from both sides.

2x 2 -2 2

Solve. (Simplify/find the solution.)

-2÷2 =

1

48

X -1

In conclusion, the correct answer is x=-1.

Answered by swathycrazy288
1

Answer:

  • 4x^2 =64-5
  • 4x^2=59
  • x^2=59÷4
  • x^2=14.75
  • √x=√14.75
  • x=3.84

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