Question

Solve for X :4root 3x^+5x-2root3

Answer 1

yeah sure for your help

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Thanks !

Here is your answer which you are searching for

$\sqrt[4]{3} x^{2} + 5x-\sqrt[2]{3}$

Compare with $ax^{2} + bx + c =0$

D = $b^{2} -4ac$

D = $5^{2} -4 . (\sqrt[-2]{3} ) . \sqrt[4]{3}$

D = 25 +96 = 121

So , x = $\frac{-b+-\sqrt{D}}{2a}$

==> $\frac{-5+11}{\sqrt[8]{3}} or \frac{-5-11}{\sqrt[8]{3}}$

==> $\frac{6}{\sqrt[8]{3}} or \frac{-16}{\sqrt[8]{3}}$

==> x =$\frac{\sqrt{3}}{4} or \frac{\sqrt[-2]{3}}{3}$

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Hope it helps !

Warm Regards

@ Brainlestuser

Answer 2

hi mate,

4√3 x² +5x -2√3 =0

⇒4√3 x² +8x -3x -2√3=0

⇒4x(√3 x+2) -√3(√3x +2) =0

⇒(√3x +2)(4x -√3) =0

⇒(√3x +2) =0 or (4x-√3) =0

⇒x = -2/√3 or √3/4

i hope it helps you.