Question

Solve for x : 4sin^2x-4cosx=1

Answer 1

hope it helps u out  dude

Answer 2

4(sinx)²-4cosx=1

• (sinx)²+(cosx)²=1   ⇒(sinx)²=1-(cosx)²

⇒4(1-(cosx)²)-4cosx=1

⇒4-4(cosx)²-4cosx=1

⇒4(cosx)²+4cosx-3=0

⇒4(cosx)²-2cosx+6cosx-3=0

⇒2cosx(2cosx-1)+3(2cosx-1)=0

⇒(2cosx-1)(2cosx+3)=0

⇒cosx=1/2

∴x=π/6+nπ.