Solve for x, 4x^2 - 2(a^2b^2)x + a^2b^2 = 0
Marzuqa:
Its algebra Oh God Pls forgive me its my worst subject I cant help at all!!! :(
Just for instance you wrote the question correct right?
yes, im sure
is there any plus between a^2 and b^2
sorry xD its 4x^2 - 2(a^2 + b^2)x + a^2b^2 = 0
Told you
Done :)))))))))))))))))))))
Thanks :D
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4x^2 - 2(a^2 + b^2)x + a^2b^2 = 0
=>4x^2 - 2a^2x - 2b^2x + a^2b^2 = 0
=>2x(2x - a^2) - b^2(2x+a^2)
=>(2x+a^2)(2x-b^2)
so value of x are -(a^2/2) and (b^2/2)
=>4x^2 - 2a^2x - 2b^2x + a^2b^2 = 0
=>2x(2x - a^2) - b^2(2x+a^2)
=>(2x+a^2)(2x-b^2)
so value of x are -(a^2/2) and (b^2/2)
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