Math, asked by sreelakshmi6, 26 days ago

solve for x(4x/(x-2) -3x/(x-1) =7 1/2)​

Answers

Answered by dipanshu9061
1

Answer:

solution x[4x²-4x-3x²+6x]/x²-x-2x+2=15/2

x[x²+2x]/x²-3x+2=15/2

[x³+2x²]/x²-3x+2=15/2

2x³+4x²=15x²-45x+30

2x³-11x²+45x-30=0

Answered by OoINTROVERToO
4

Step-by-step explanation:

 \bf \frac{4x}{(x-2) }-  \frac{3x}{(x-1)} =7  \frac{1}{2} \\  \\ \bf \frac{4x}{(x-2) }-  \frac{3x}{(x-1)} = \frac{15}{2}  \\  \\ \bf \frac{4x(x - 1) - 3x(x - 2)}{(x-2)(x-1)} =  \frac{15}{2}  \\  \\ \bf \frac{4 {x}^{2}   - 4x- 3 {x}^{2}   + 6x}{ {x}^{2} - 3x + 2 } =  \frac{15}{2}  \\  \\  \bf \frac{ {x}^{2}    + 2x}{ {x}^{2} - 3x + 2 } =  \frac{15}{2} \\  \\  \bf2 {x}^{2}   + 4x = 15 {x}^{2}  - 45x + 30 \\  \\ \bf13 {x}^{2}  - 49x + 30 = 0 \\  \\ \bf13 {x}^{2}  - 39x - 10x + 30 = 0  \\  \\ \bf13 {x}(x - 3) - 10(x - 3) = 0  \\  \\ \bf(x - 3)(13x - 10) = 0 \\  \\    \large  \leadsto\blue{ \boxed{ \pmb {\tt{x= 3 \:  \: or \:  \:  \frac{10}{13} }}}}

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