Math, asked by samdisha3911, 5 months ago

solve for x. 4x2-2(a²+b²)x+a²b²=0

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Answered by Imblank

1

Answer:

4x²-2(a²+b²)x+a²b²

= 4x²-2a²x-2b²x+a²b²

= 2x(2x-a²)-b²(2x-a²)

= (2x-a²)(2x-b²)

2x-a² = 0

2x = a²

x = a²/2

2x-b² = 0

2x = b²

x = b²/2

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