Question

solve for x, 5√3/x+7√x/3=68/3
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Answer 1

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$\frac{5 \sqrt{3} }{x} + \frac{7 \sqrt{x} }{3} = \frac{68}{3} \\ \\ = > \frac{15 \sqrt{3 }{+ 7x \sqrt{x} } }{3x} = \frac{68}{3} \\ \\ = > 15 \sqrt{3} + 7x \sqrt{x} = \frac{68}{3} \times 3x \\ \\ = > 15 \sqrt{3} + 7x \sqrt{x} = 68x$

i tried some of its process............

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