Math, asked by HimanshiKankane, 1 year ago

Solve for x: 5^logx -3^log(x-1)=3^log(x+1) -5^log(x-1 )where the base logarithm is 10

Answers

Answered by ankursarwankar2003
2

Answer:

x=-1\2 or x=-1

Step-by-step explanation:

logx^5-log(x-1)^3=log(x+1)^3-log(x-1)^5

accordint to the property of log

log x^5\(x-1)^3=log (x+1)^3\(x-1)^5

x^5=(x+1)^3

x^5=x^3+3x^2+3x+1

x^2=3x^2+3x+1

3x^2+3x+1-x^2=0

2x^2+3x+1=0

x=-1\2    or x=-1

Answered by AaryanKhedekar
2

Answer:

x=-1\2 or x=-1

Step-by-step explanation:logx^5-log(x-1)^3=log(x+1)^3-log(x-1)^5

accordint to the property of log log

x^5\(x-)^3=log(x+1)^3\(x-)^5x^5=(x+1)^3x^5=x^3+3x^2+3x+1x^2=3x^2+3x+13x^2+3x+1-x^2=02x^2+3x+1=0x=-1\2    or x=-1

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