Question

Solve for x:
....................

Answer 1

please mark it as brainliest !!!

Answer 2

$\sqrt{6x + 7} - (2x - 7) = 0 \\ \\\sqrt{6x + 7} = (2x - 7) \\ \\ {(\sqrt{6x + 7 \: })}^{2} ={ (2x - 7)}^{2}$

$6x + 7 = 4 {x}^{2} - 28x + 49$

$4 {x}^{2} - 28x + 49 - 6x - 7 = 0 \\ \\ 4 {x }^{2} - 34x + 42 = 0$

$x = \frac{ - ( - 34) \pm \sqrt{ {34}^{2} - 4 \times 4 \times 42 } }{2 \times 4} \\ \\ x = \frac{ 34 \pm \sqrt{ 1156-672 } }{8}$

$x = \frac{ 34 \pm \sqrt{ 484 } }{8} \\ \\ x = \frac{ 34 \pm 22 }{8}$

$x = \frac{ 34 + 22 }{8} \: \: \: and \: \: \: \frac{ 34 - 22 }{8} \\ \\ x = \frac{56}{8} \: \: \: and \: \: \: \frac{ 12 }{8}$

$\boxed{x = 7 \: \: \: and \: \: \: 1.5}$