Question

solve for x 6^2x^2+(b^2-q2)x=0​

Answer 1

Step-by-step explanation:

\left[x _{3}\right] = \left[ \left( \frac{1}{6}\,i \right) \,\sqrt{\left( b^{2}-q2\right) }\right][x

3

]=[(

6

1

i)√

(b

2

−q2)

]