Question

Solve for x: 6(x²-1/x²)-25(x-1/x)+12=0

Please solve this question.....​

Answer 1

$\huge\boxed{Answer}$

6(x² - 1/x²) - 25(x - 1/x) + 12 = 0

6(x - 1/x)(x + 1/x) - 25(x - 1/x) + 12 = 0

(x - 1/x){ 6(x + 1/x) - 25 } + 12 = 0

(x - 1/x) { 6(x + 1/x) - 25 } = -12

First ,

(x - 1/x) = -12 ----------(1)

Second ,

6(x + 1/x) = 13

(x + 1/x) = 13/6 --------(2)

From eq. (1) + eq. (2) -

2x = -12 + 13/6

2x = -72/6 + 13/6

2x = -59/6

x = -59/12