Question

solve for x
7^x-2
x 7^3X-11 = 539


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Answer 1

Answer:

Since the base are the same, we add the power together

7^(x-2)+(3x-11) = 539

7^(4x-13) = 539

Divide 539 by 7

539/7 = 77

Therefore,

7^(4x-13) = 7^77

Since the base are the same, we work with the power

4x - 13 = 77

4x = 77 + 13

4x = 90

Divide both sides by 4

x = 22.5