Math, asked by jarvickanishk619, 3 months ago

Solve for x : √7x2–x -13√7= 0 .

Answers

Answered by prasannshenoy121
0

Answer:

\begin{gathered} \sqrt{7} {x}^{2} - 6x - 13 \sqrt{7} \\ \sqrt{7} {x}^{2} - 13x + 7x - 13 \sqrt{7} \\ x( \sqrt{7} x - 13) + \sqrt{7} \sqrt{7} x - 13 \sqrt{7} \\ x( \sqrt{7} x - 13) + \sqrt{7} ( \sqrt{7} x - 13) \\ ( \sqrt{7} x - 13)(x + \sqrt{7} )\end{gathered}

7

x

2

−6x−13

7

7

x

2

−13x+7x−13

7

x(

7

x−13)+

7

7

x−13

7

x(

7

x−13)+

7

(

7

x−13)

(

7

x−13)(x+

7

)

Answered by sonikashish919
3

Answer:

√7x²-x-13√7=0

13√7+√7x²-x=0

13√14+x=0

13√14= -x

x= -13√14

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