Solve for x : √7x2–x -13√7= 0 .
Answers
Answered by
0
Answer:
\begin{gathered} \sqrt{7} {x}^{2} - 6x - 13 \sqrt{7} \\ \sqrt{7} {x}^{2} - 13x + 7x - 13 \sqrt{7} \\ x( \sqrt{7} x - 13) + \sqrt{7} \sqrt{7} x - 13 \sqrt{7} \\ x( \sqrt{7} x - 13) + \sqrt{7} ( \sqrt{7} x - 13) \\ ( \sqrt{7} x - 13)(x + \sqrt{7} )\end{gathered}
7
x
2
−6x−13
7
7
x
2
−13x+7x−13
7
x(
7
x−13)+
7
7
x−13
7
x(
7
x−13)+
7
(
7
x−13)
(
7
x−13)(x+
7
)
Answered by
3
Answer:
√7x²-x-13√7=0
13√7+√7x²-x=0
13√14+x=0
13√14= -x
x= -13√14
hope it helps
please mark me brainliest
Similar questions
English,
2 months ago
Math,
3 months ago
Social Sciences,
3 months ago
English,
11 months ago
Math,
11 months ago