Question

Solve for x 8 x square + 22 x minus 21 is equal to zero

Answer 1

$\mathfrak{\huge{Answer:}}$

$\mathbb{GIVEN}$

Equation : $\sf{8x^{2} + 22x - 21}$

$\mathbb{TO\:FIND}$

The value of x in this equation.

$\mathbb{METHOD}$

What we'll do is just simply take out the value of x in this equation by the method of $\bf{factorisation}$.

Product of numbers = (-168)

Sum of numbers = 22

The numbers with the same features = $\tt{28\:and\:6}$

Equation formed will be :-

$\sf{8x^{2} + 28x - 6x - 21}$

Take the common numbers :-

=》 $\sf{4x (2x + 7) -3 (2x + 7)}$

Solve this formed equation further

=》 $\sf{(4x - 3) (2x + 7)}$

=》 $\sf{x = \frac{3}{4}\:and\:x = \frac{(-7)}{2}}$

There's your answer !