Question

Solve for x: 81^-2÷729^1-x=9^2x

Answer 1

Answer:

{81^-2}/{729^(1-x)} = 9^2x

81^-2 = 9^(2×-2) = 9^-4

729^(1-x) = 9^3(1-x) = 9^(3-3x)

a^b/a^c. = a ^ b-c

a^b/a^c. = a ^ b-cafter applying this rule

9^ {-4-(3-3x)}. = 9^2x

9^{-4-3+3x} =9^2x

9^(-7+3x) =9^2x

a^b=a^c

than b=c

after applying this rule

-7+3x =2x

3x-2x = 7

x =7

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