Question

Solve for x :
8x^2 - 2x - 3 = 0​

Answer 1

$8 {x}^{2} - 2x - 3 = 0 \\ 8 {x}^{2} + 4x - 6x - 3 = 0 \\ 4x(2x + 1) - 3(2x + 1) = 0 \\ (2x + 1)(4x - 3) = 0 \\ x = \frac{ - 1}{2} \: or \: x = \frac{3}{4}$

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