Question

solve for x: 8x^2-8√2x+4

Answer 1

heya,..☺

8x^2-8√2x+4=0

=)4(2x^2+2√2x+1)

=)【2x+2√2x+1】=0

=)now by using quadratic formulae
.roots =-2√2+-√8-4*2*4/2*2√2

roots=-2√2-+√-24/4√2

but when we finding the roots we saw that Discriminant is in negative form ,so it has no real roots .

hope it help you

@rajukumar☺