Math, asked by Ksgopika, 1 year ago

Solve for x:
9(x^2+1/x^2)-9(x+1/2)-52=0

Answers

Answered by Arnavchawla501
2
9(x^2+1/x^2)-9(x+1/2)-52=0
9(x2+1/x2)-9x-4.5-52=0
9x2+9/9x2-9x-56.5=0
9-9x-56.5=0
-9x=64.5
x=-64.5/9=-7.16 with a bar on 6
Answered by tardymanchester
4

Answer:

x=-2,-0.4,0.39,3

Step-by-step explanation:

Given : 9(x^2+\frac{1}{x^2})-9(x+\frac{1}{2})-52=0

To find : Solve for x?

Solution :

9(x^2+\frac{1}{x^2})-9(x+\frac{1}{2})-52=0

9x^2+\frac{9}{x^2}-9x-\frac{9}{2}=52

\frac{18x^4+18-18x^3-9x^2}{2x^2}=52

18x^4+18-18x^3-9x^2=104x^2

18x^4-18x^3-113x^2+18=0

The solution of the given equation graphically shows the points on x-axis are x=-2,-0.4,0.39,3

Refer the attached figure below.

Attachments:
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