Question

Solve for x 9x^2 -6ax +(a^2-b^2 ) =0

Answer 1

Hi ,

9x² - 6ax + ( a² - b² ) = 0

9x²-3(a + b )x -3( a - b )x + (a² - b²)= 0

3x[3x - (a + b)] -(a - b )[3x - ( a + b )]= 0

[ 3x -( a + b ) ][ 3x - ( a - b ) ] = 0

Therefore ,

3x - ( a+ b ) = 0 or 3x - ( a - b ) = 0

3x= ( a + b ) or 3x = ( a - b )

x = ( a + b ) / 3 or x = ( a - b ) / 3

I hope this helps you.

:)

Answer 2

HEY MATE YOUR ANSWER IS AS FOLLOWS

Consider 9x2 - 6ax + a2 - b2 
= 0 9x2 – 6ax + (a – b)(a + b)
= 0 9x2 – 3x(a – b) – 3x(a + b) + (a – b)(a + b)
= 0 3x[3x – (a – b)] – (a + b) [3x – (a – b)]
 = 0 [3x – (a – b)][3x – (a + b)]  
= 0 [3x – (a – b)] = 0 or [3x – (a + b)]
= 0 3x = (a – b) or 3x = (a + b)
 ∴ x = (a – b)/3 or x = (a + b)/3

HOPE THIS WILL HELP YOU......