Math, asked by Ãbćd, 1 year ago

solve for x:9x^2-6b^2x-(a^4-b^4)=0

Answers

Answered by littyissacpe8b60
310

9x² - 6b²x - (a⁴ - b⁴) =0

9x² - 3x (2b²) + (b² - a²) (b² + a²)

9x² - 3(b² - a² + b² + a²)x + (b² - a²) (b²+ a²)

9x² - 3(b² - a²)x - 3(b² + a²)x + (b² - a²) (b² + a²)

3x(3x - b² + a²) - (b² + a²) (3x - b² + a²)

(3x - b² - a²) (3x - b² + a²)

x  =        b²  +  a²    ,       b² - a²  

                  3                       3


x  =        b²  +  a²    ,       (b - a) (b + a)  

                  3                           3


At last finished. Too much time needed. Any way you can ask if you have any doubts




Ãbćd: sir u have done it by middle term splitting
Answered by sandeepbiswas267
82

Answer:

Step-by-step explanation:

9x² - 6b²x - (a⁴ - b⁴) =0

9x² - 3x (2b²) + (b² - a²) (b² + a²)

9x² - 3(b² - a² + b² + a²)x + (b² - a²) (b²+ a²)

9x² - 3(b² - a²)x - 3(b² + a²)x + (b² - a²) (b² + a²)

3x(3x - b² + a²) - (b² + a²) (3x - b² + a²)

(3x - b² - a²) (3x - b² + a²)

x  =        b²  +  a²    ,       b² - a²  

/ /

                  3                       3

x  =        b²  +  a²    ,       (b - a) (b + a)  

/ /

                  3                           3

At last finished.

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