CBSE BOARD X, asked by mayahimanshi, 9 months ago

solve for x 9x2-6a2x+(a4-b4)​

Answers

Answered by tanvivyas123456
4

Answer:

Consider, 9x2 _ 6a2x + (a4 _ b4) = 0

9x2 _ 3(a2 + b2 + a2 _ b2)x + (a4 _ b4) = 0

9x2 _  3(a2 + b2 )x - 3(a2 _ b2)x + [(a2 + b2 )(a2 _ b2)] = 0

3x [x _  (a2 + b2 )] - 3(a2 _ b2)[x - (a2 + b2 )]= 0

[x _  (a2 + b2 )][3x  - 3(a2 _ b2)]= 0

[x _  (a2 + b2 )] = 0 or [3x - 3(a2 _ b2)]= 0

x = (a2 + b2) or (a2 - b2 )

Explanation:

9x2_6a2x+(a4_b4) = 0

Similar questions