solve for x 9x2-6a2x+(a4-b4)
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Answer:
Consider, 9x2 _ 6a2x + (a4 _ b4) = 0
9x2 _ 3(a2 + b2 + a2 _ b2)x + (a4 _ b4) = 0
9x2 _ 3(a2 + b2 )x - 3(a2 _ b2)x + [(a2 + b2 )(a2 _ b2)] = 0
3x [x _ (a2 + b2 )] - 3(a2 _ b2)[x - (a2 + b2 )]= 0
[x _ (a2 + b2 )][3x - 3(a2 _ b2)]= 0
[x _ (a2 + b2 )] = 0 or [3x - 3(a2 _ b2)]= 0
x = (a2 + b2) or (a2 - b2 )
Explanation:
9x2_6a2x+(a4_b4) = 0
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