Question

solve for x 9x2-6b2x-(a4-b4)​

Answer 1

Factorization is a bit complex instead you can use quadratic formula,  but as you have asked so:

9x²-6b²x-(a^4-b^4)=0

9x²-3(2b²)x-(a^4-b^4)=0

9x²-3(b²-a²+b²+a²)x+(b^4-a^4)=0

9x²-3(b²-a²)x-3(b²+a²)x+(b²+a²)(b²-a²)=0

3x(3x-b²+a²)-(b²+a²)(3x-b²+a²)=0

(3x-b²-a²)(3x-b²+a²)=0

ans: 18x-12bx-4a+4b

Answer 2

9x^-6b^x - (a^4-b^4) =0

step by step answer

9x^-6b^x -a^4 - a^4+b^4 =0

(3x^) -6b^x +(b^) -a^4 =0

(3x-b^)^ - (a^)^ =0

(3x-b^+a^) (3x-b^-a^) =0

1. 3x-b^+a^=0
2. 3x=b^-a^
3. X=b^-a^/3

• or, 3x-b^-a^=0
• 3x=a^+b^
• X=a^+b^/ 3