Math, asked by sayantanisingha, 1 year ago

Solve for x: a^2b^2x^2-(4b^2-3a^2)x-12a^2b^2=0

Answers

Answered by Karan2302
0
Use quadratic formula

sayantanisingha: I need to verify my answe
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sayantanisingha: So could you please tell the answer
Answered by vk22025vicky
10
must be:a2b2x2- (4b4- 3a4)x -12a2b2= 0⇒ a2b2x2- 4b4x+ 3a4x -12a2b2= 0⇒ b2x(a2x - 4b2)+ 3a2(a2x - 4b2) = 0⇒ (a2x - 4b2)(b2x+ 3a2) = 0⇒ (a2x - 4b2) = 0 or (b2x+ 3a2) = 0⇒ a2x = 4b2or b2x= - 3a2⇒ x = 4b2/a2or x= - 3a2/b2.I hope this answer is helpful to you
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