Question

Solve for x

a) 5^(2x) ÷ 5^(7) = 5^3
b)3^(2x)*9=27​

Answer 1

Answer:

a) 2x = log (base of 5 ) (5^3 * 5^7)

b) 2x * 9 = log (base of 3) (27)

Answer 2

Answer:

Step-by-step explanation:

a) 5^(2x )÷ 5^(7) = 5^3

5^(2x )/5^(7) = 5^3

5^(2x ) = 5^3 × 5^7

5^(2x ) = 5^(3 +7) [ bases are equal then powers should be add ]

5^(2x ) = 5^10

2x = 10 [bases are equal then powers should be equal ]

x = 10/2

x = 5.

b) 3^(2x )× 9 = 27

3^(2x ) × 3^2 = 3^3

3^(2x ) = 3^3 / 3^2

3^(2x ) = 3^3 × 3^(-2) [1/a = a^(-1)]

3^(2x ) = 3^(3-2) [ bases are equal then powers should be add ]

3^(2x ) = 3^1

2x = 1 [ bases are equal then powers should be equal ]

x = 1/2.