Question

Solve for x :
a(a² +b^2) x² + b²x - a=0​

Answer 1

Step-by-step explanation:

a(a²+b²)x² + b²x - a= 0

=>a³x² + ab²x² + b²x - a = 0

=>a³x² - a + ab²x² + b²x = 0

=>a(a²x²-1) + b²x(ax+1) = 0

=>a(ax+1)(ax-1) + b²x(ax+1) = 0

=>(ax+1) {a(ax-1) + b²x} = 0

either x=-1/a

or a(ax-1)+b²x=0

=>a²x-a+b²x=0

=>x(a²+b²)=a

=>x = a/(a²+b²)

Answer 2

Answer:

hope it will helps yours mate